Will a What Items (25x18x13 cm) Fit in a Container?

−0.5 in over

· ON THE HEIGHT AXIS

It exceeds the opening at the tightest point.

The height axis runs out of room.
Checked all 6 orientations — none fits.
A <1 in handling allowance is already subtracted.

5 in vs 4 in

Overage −0.5 in (−11.4%) on the HEIGHT axis

AVolume inequality✓ PASS

\sum V_{\text{item}} \;\le\; V_{\text{container}}

↓ SUBSTITUTE

350 \;\overset{?}{\le}\; 502

Plain English: Packed together the item fills about 70% of the space's volume — plenty of room by volume.

BAxis inequality · length✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

7 \;\overset{?}{\le}\; 10\quad(\text{length})

↓ EVALUATE

7\,\text{in} \;\le\; 10\,\text{in} \;\Longrightarrow\; \Delta = +3\,\text{in}

Plain English: Along the length, the item is 7 in and the space allows 10 in — 3 in to spare.

CAxis inequality · width✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

10 \;\overset{?}{\le}\; 11.2\quad(\text{width})

↓ EVALUATE

10\,\text{in} \;\le\; 11.2\,\text{in} \;\Longrightarrow\; \Delta = +1.2\,\text{in}

Plain English: Along the width, the item is 10 in and the space allows 11.2 in — 1.2 in to spare.

DAxis inequality · height✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

5 \;\overset{?}{\le}\; 4.5\quad(\text{height})

↓ EVALUATE

5\,\text{in} \;>\; 4.5\,\text{in} \;\Longrightarrow\; \Delta = -0.5\,\text{in}

Plain English: Along the height, the item is 5 in and the space allows 4.5 in — over by 0.5 in.

EDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{7^2 + 10^2} \;\overset{?}{\le}\; \sqrt{10^2 + 11.2^2}

↓ EVALUATE

12.2\,\text{in} \;\le\; 15\,\text{in} \;\Longrightarrow\; \Delta = +2.8\,\text{in}

Plain English: Tilted corner-to-corner the face spans 12.2 in, inside the opening's 15 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{7^2 + 10^2 + 5^2}

↓ EVALUATE

13.2\,\text{in} \;\le\; 15.7\,\text{in} \;\Longrightarrow\; \Delta = +2.5\,\text{in}

Plain English: Corner to corner the item reaches 13.2 in — keep that swing room in mind for the turn after.

Orientation	L	W	H	Result	Note
254×178×127mm (Upright)	3 cm	7.6 cm	-1.3 cm	✕	Length
254×127×178mm (On its side)	3 cm	12.7 cm	-6.4 cm	✕	Length
178×254×127mm (Rotated 90°)	10.6 cm	0 cm	-1.3 cm	✕	Length
178×127×254mm (On its side)	10.6 cm	12.7 cm	-14 cm	✕	Length
127×254×178mm (On its side)	15.7 cm	0 cm	-6.4 cm	✕	Length
127×178×254mm (On its side)	15.7 cm	7.6 cm	-14 cm	✕	Length

How the container-fit check works

A container is a fully 3D box — length, width, AND height must accept the item simultaneously; corner reachability is a soft second constraint.

Treat the container as a 3D box and generate the item’s 6 dimension permutations (3 axes × 2 flips).
For each permutation, apply the constraint: item ≤ container on length, width, and height simultaneously.
Check reachability — items longer than arm’s reach can’t be loaded all the way into the back corners.
Subtract 1.5 in handling clearance on each axis for the mover’s grip plus pivot room.
Verdict ladder (verdict-tiers.js, shared with door): FITS ≥ 2 in; FITS_TIGHT 0.5–2 in; FITS_VERY_TIGHT 0–0.5 in; DOESN'T_FIT below.

Interior dimensions use the published spec; door rails, ribs, and floor lashings can shave 1–2 in off the usable corners.

Similar calculations

10 in Width 16 1⁄2 Height 1⁄4 Length 73 Weight 57 Lb Oz in a 15 in containerFITS

10 in Generic Item in a 24 in containerFITS

13 in Shoes in a 5 ft containerFITS

5 in Box in a 6 in containerDOESN'T FIT

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Will a what items (25x18x13 cm) fit in a container?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check