Will a chair (94x80x89 cm) Fit in a Container?

−0.5 in over

· ON THE HEIGHT AXIS

It exceeds the opening at the tightest point.

The height axis runs out of room.
Checked all 6 orientations — none fits.
A <1 in handling allowance is already subtracted.

31 in vs 31 in

Overage −0.5 in (−2.4%) on the HEIGHT axis

AVolume inequality✓ PASS

\sum V_{\text{item}} \;\le\; V_{\text{container}}

↓ SUBSTITUTE

40796 \;\overset{?}{\le}\; 81144

Plain English: Packed together the item fills about 50% of the space's volume — plenty of room by volume.

BAxis inequality · length✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

37 \;\overset{?}{\le}\; 40.7\quad(\text{length})

↓ EVALUATE

37\,\text{in} \;\le\; 40.7\,\text{in} \;\Longrightarrow\; \Delta = +3.7\,\text{in}

Plain English: Along the length, the item is 37 in and the space allows 40.7 in — 3.7 in to spare.

CAxis inequality · width✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

35 \;\overset{?}{\le}\; 64.8\quad(\text{width})

↓ EVALUATE

35\,\text{in} \;\le\; 64.8\,\text{in} \;\Longrightarrow\; \Delta = +29.8\,\text{in}

Plain English: Along the width, the item is 35 in and the space allows 64.8 in — 29.8 in to spare.

DAxis inequality · height✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

31.5 \;\overset{?}{\le}\; 30.7\quad(\text{height})

↓ EVALUATE

31.5\,\text{in} \;>\; 30.7\,\text{in} \;\Longrightarrow\; \Delta = -0.7\,\text{in}

Plain English: Along the height, the item is 31.5 in and the space allows 30.7 in — over by 0.7 in.

EDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{37^2 + 35^2} \;\overset{?}{\le}\; \sqrt{40.7^2 + 64.8^2}

↓ EVALUATE

50.9\,\text{in} \;\le\; 76.5\,\text{in} \;\Longrightarrow\; \Delta = +25.6\,\text{in}

Plain English: Tilted corner-to-corner the face spans 50.9 in, inside the opening's 76.5 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{37^2 + 35^2 + 31.5^2}

↓ EVALUATE

59.9\,\text{in} \;\le\; 82.5\,\text{in} \;\Longrightarrow\; \Delta = +22.6\,\text{in}

Plain English: Corner to corner the item reaches 59.9 in — keep that swing room in mind for the turn after.

Orientation	L	W	H	Result	Note
940×800×889mm (Upright)	—	2 ft 4 in	-4 in	✕	Height
940×889×800mm (On its side)	—	2 ft 4 in	-0.5 in	✕	Height
800×940×889mm (Rotated 90°)	—	2 ft 9.5 in	-4 in	✕	Height
800×889×940mm (On its side)	—	2 ft 9.5 in	-6 in	✕	Height
889×940×800mm (On its side)	—	2 ft 6 in	-0.5 in	✕	Height
889×800×940mm (On its side)	—	2 ft 6 in	-6 in	✕	Height

How the container-fit check works

A container is a fully 3D box — length, width, AND height must accept the item simultaneously; corner reachability is a soft second constraint.

Treat the container as a 3D box and generate the item’s 6 dimension permutations (3 axes × 2 flips).
For each permutation, apply the constraint: item ≤ container on length, width, and height simultaneously.
Check reachability — items longer than arm’s reach can’t be loaded all the way into the back corners.
Subtract 1.5 in handling clearance on each axis for the mover’s grip plus pivot room.
Verdict ladder (verdict-tiers.js, shared with door): FITS ≥ 2 in; FITS_TIGHT 0.5–2 in; FITS_VERY_TIGHT 0–0.5 in; DOESN'T_FIT below.

Interior dimensions use the published spec; door rails, ribs, and floor lashings can shave 1–2 in off the usable corners.

Similar calculations

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3 ft Inch Tv 1 in a 5 ft containerDOESN'T FIT

3 ft 75-Inch TV in a 4 ft containerFITS TIGHT

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Will a chair (94x80x89 cm) fit in a container?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check