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Will a dresser (152x61x76 cm) fit in a container?

dresser· 5 ft × 24 in × 30 in

+2 ft 8 in (+14%)of clearance at tightest point

Item being fitted

dresser5 ft × 24 in × 30 in

Space clearance

Container5 ft 10 in × 10 ft 4 in × 4 ft 8 in

Result

2 ft 8 in of clearance

▸ width axis · binding

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Expert analysis

A dresser measuring 60 in × 24 in × 30 in likely fits in a container, with about 2 ft 8 in to spare at the tightest point. The binding dimension is height: that is the axis where the dresser runs out of room. The persisted calculation steps support the reported tightest-point margin. One caveat: checked as one rigid piece: not compressed, bent, or taken apart.

How we verified this

Binding axis: Height
Tightest clearance: 2 ft 8 in clear
Result: Review the recorded result

+2 ft 8 in clearance

· ON THE HEIGHT AXIS

Here’s what we found.

The height axis runs out of room.
A <1 in handling allowance is already subtracted.

24 in vs 4 ft 8 in

Clearance +2 ft 8 in (+57.1%) on the HEIGHT axis

AVolume inequality✓ PASS

\sum V_{\text{item}} \;\le\; V_{\text{container}}

↓ SUBSTITUTE

43228 \;\overset{?}{\le}\; 486005

Plain English: Packed together the item fills about 9% of the space's volume — plenty of room by volume.

BAxis inequality · width✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

30 \;\overset{?}{\le}\; 70\quad(\text{width})

↓ EVALUATE

30\,\text{in} \;\le\; 70\,\text{in} \;\Longrightarrow\; \Delta = {+40}\,\text{in}

Plain English: Along the width, the item is 30 in and the space allows 70 in — 40 in to spare.

CAxis inequality · depth✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

60 \;\overset{?}{\le}\; 124\quad(\text{depth})

↓ EVALUATE

60\,\text{in} \;\le\; 124\,\text{in} \;\Longrightarrow\; \Delta = {+64}\,\text{in}

Plain English: Along the depth, the item is 60 in and the space allows 124 in — 64 in to spare.

DAxis inequality · height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

24 \;\overset{?}{\le}\; 56\quad(\text{height})

↓ EVALUATE

24\,\text{in} \;\le\; 56\,\text{in} \;\Longrightarrow\; \Delta = {+32}\,\text{in}

Plain English: Along the height, the item is 24 in and the space allows 56 in — 32 in to spare.

E3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{30^2 + 60^2 + 24^2}

↓ EVALUATE

71.3\,\text{in} \;\le\; 153\,\text{in} \;\Longrightarrow\; \Delta = {+81.8}\,\text{in}

Plain English: Corner to corner the item reaches 71.3 in — keep that swing room in mind for the turn after.

Orientation	L	W	H	Result	Note
✓ chosen1524×609.5999999999999×762mm (Upright)	—	10 in	26 in	✓
1524×762×609.5999999999999mm (On its side)	—	10 in	32 in	✓
609.5999999999999×1524×762mm (Rotated 90°)	—	46 in	26 in	✓
609.5999999999999×762×1524mm (On its side)	—	46 in	-4 in	✕	Too wide
762×1524×609.5999999999999mm (On its side)	—	40 in	32 in	✓
762×609.5999999999999×1524mm (On its side)	—	40 in	-4 in	✕	Too wide

Margins shown are calculated; allow ±¼ in for tape-measure precision.

How the container-fit check works

A container is a fully 3D box — length, width, AND height must accept the item simultaneously; corner reachability is a soft second constraint.

Treat the container as a 3D box and generate the item’s 6 dimension permutations (3 axes × 2 flips).
For each permutation, apply the constraint: item ≤ container on length, width, and height simultaneously.
Check reachability — items longer than arm’s reach can’t be loaded all the way into the back corners.
Subtract 1.5 in handling clearance on each axis for the mover’s grip plus pivot room.
Verdict ladder (verdict-tiers.js, shared with door): FITS ≥ 2 in; FITS_TIGHT 0.5–2 in; FITS_VERY_TIGHT 0–0.5 in; DOESN'T_FIT below.

Interior dimensions use the published spec; door rails, ribs, and floor lashings can shave 1–2 in off the usable corners.

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Will a dresser (152x61x76 cm) fit in a container?

Expert analysis

Here’s what we found.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check