Item Fits

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DOESN'T FIT

It doesn't fitby 3 ft 6 in too large

Will a mattress (190x135x31 cm) fit in a room?

mattress· 6 ft 3 in × 4 ft 5 in × 12 in

−3 ft 6 in (−374%)too large at tightest point

Item being fitted

mattress6 ft 3 in × 4 ft 5 in × 12 in

Space clearance

Room6 ft 5 in × 11 in × 8 ft

Result

3 ft 6 in too large

▸ depth axis · binding

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Expert analysis

A mattress measuring 75 in × 53 in × 12 in does not fit in a room, but it's about 3 ft 6 in too large at the tightest point. One caveat: item is rigid and cannot be compressed, bent, or disassembled.

How we verified this

Binding axis: Room short
Tightest clearance: 3 ft 6 in over
Result: Room short does not clear

−3 ft 6 in over

· ON THE DEPTH AXIS

It exceeds the opening at the tightest point.

Your mattress will not fit in the room — and it is clearly over the limit at the tightest point.

Handling: The item exceeds the space in every orientation — standard entry won't work.

4 ft 5 in vs 11 in

Overage −3 ft 6 in (−373.7%) on the DEPTH axis

ARoom coverage ratio✕ FAIL

\text{coverage} = \dfrac{A_{\text{item}}}{A_{\text{room}}}

↓ SUBSTITUTE

\dfrac{3976}{861}

Plain English: Share of the room floor consumed by the placed item.

BAxis inequality · room short✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

53.1 \;\overset{?}{\le}\; 11.2\quad(\text{room short})

↓ EVALUATE

53.1\,\text{in} \;>\; 11.2\,\text{in} \;\Longrightarrow\; \Delta = {-41.9}\,\text{in}

Plain English: Along the room short, the item is 53.1 in and the space allows 11.2 in — over by 41.9 in.

CMinimum required space · room short✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

53.1 + 0 = 53.1

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

DLargest item that fits · room short✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

11.2 - 0 = 11.2

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

EDiagonal clearance · Pythagorean✕ FAIL

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{74.8^2 + 53.1^2} \;\overset{?}{\le}\; \sqrt{76.8^2 + 11.2^2}

↓ EVALUATE

91.8\,\text{in} \;>\; 77.6\,\text{in} \;\Longrightarrow\; \Delta = {-14.2}\,\text{in}

Plain English: Even tilted corner-to-corner the face spans 91.8 in, past the opening's 77.6 in diagonal — angling it doesn't recover the fit.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{74.8^2 + 53.1^2 + 12.2^2}

↓ EVALUATE

92.6\,\text{in} \;\le\; 123.5\,\text{in} \;\Longrightarrow\; \Delta = {+30.9}\,\text{in}

Plain English: Corner to corner the item reaches 92.6 in — keep that swing room in mind for the turn after.

Orientation	Strategy	Result
0° (as-is), long wall	—	✕
0° (as-is), short wall	—	✕
90° rotated, long wall	—	✕
90° rotated, short wall	—	✕
diagonal (1°–89°)	—	✕

How the room-fit check works

A room is a 2D footprint — width and depth matter for placement, plus the walkway gap left between the item and walls or other obstacles.

Place the item footprint inside the room rectangle in the orientation it will be used.
Compute walkway gaps from each item edge to every wall and to other obstacles in the room.
Take the minimum walkway gap — that’s the daily-traffic clearance the room must support.
Verdict ladder (getRoomVerdictTier): walkway <18 in DOESN'T_FIT; 18–24 VERY_TIGHT; 24–36 TIGHT; 36–48 FITS; ≥48 confident FITS.

Walkway thresholds use standard ergonomic minimums; a confident mover may negotiate gaps tighter than the recommended tier.

Similar calculations

6 ft mattress in a 10 ft roomFITS

6 ft King mattress (76"×80"×12") in a 12 ft roomFITS

6 ft mattress in a 11 in roomDOESN'T FIT

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Will a mattress (190x135x31 cm) fit in a room?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check