Item Fits

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DOESN'T FIT

It doesn't fitby <1 in too large

Will a queen size bed (152x203x36 cm) fit in a room?

queen size bed· 5 ft × 6 ft 8 in × 14 in

−<1 in (−446%)too large at tightest point

Item being fitted

queen size bed5 ft × 6 ft 8 in × 14 in

Space clearance

Room11 in × 13 ft 6 in × 8 ft

Result

<1 in too large

▸ width axis · binding

See more queen size bed room calculations →

Expert analysis

A queen size bed measuring 60 in × 80 in × 14 in does not fit in a room, but it's about <1 in too large at the tightest point.

How we verified this

Binding axis: Room short
Tightest clearance: <1 in over
Result: Room short does not clear

−4 ft 1 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

Your queen size bed will not fit in the room — but only just — it is a hair over the limit at the tightest point.

Handling: The item exceeds the space in every orientation — standard entry won't work.

5 ft vs 11 in

Overage −4 ft 1 in (−446.2%) on the WIDTH axis

ARoom coverage ratio✕ FAIL

\text{coverage} = \dfrac{A_{\text{item}}}{A_{\text{room}}}

↓ SUBSTITUTE

\dfrac{4800}{1780}

Plain English: Share of the room floor consumed by the placed item.

BAxis inequality · room short✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

60 \;\overset{?}{\le}\; 11\quad(\text{room short})

↓ EVALUATE

60\,\text{in} \;>\; 11\,\text{in} \;\Longrightarrow\; \Delta = -49\,\text{in}

Plain English: Along the room short, the item is 60 in and the space allows 11 in — over by 49 in.

CMinimum required space · room short✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

60 + 0 = 60

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

DLargest item that fits · room short✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

11 - 0 = 11

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

EDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{80^2 + 60^2} \;\overset{?}{\le}\; \sqrt{162^2 + 11^2}

↓ EVALUATE

100\,\text{in} \;\le\; 162.4\,\text{in} \;\Longrightarrow\; \Delta = +62.4\,\text{in}

Plain English: Tilted corner-to-corner the face spans 100 in, inside the opening's 162.4 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{80^2 + 60^2 + 14^2}

↓ EVALUATE

101\,\text{in} \;\le\; 188.7\,\text{in} \;\Longrightarrow\; \Delta = +87.7\,\text{in}

Plain English: Corner to corner the item reaches 101 in — keep that swing room in mind for the turn after.

Orientation	Strategy	Result
0° (as-is), short wall	—	✕
0° (as-is), long wall	—	✕
90° rotated, short wall	—	✕
90° rotated, long wall	—	✕
diagonal (1°–89°)	—	✕

How the room-fit check works

A room is a 2D footprint — width and depth matter for placement, plus the walkway gap left between the item and walls or other obstacles.

Place the item footprint inside the room rectangle in the orientation it will be used.
Compute walkway gaps from each item edge to every wall and to other obstacles in the room.
Take the minimum walkway gap — that’s the daily-traffic clearance the room must support.
Verdict ladder (getRoomVerdictTier): walkway <18 in DOESN'T_FIT; 18–24 VERY_TIGHT; 24–36 TIGHT; 36–48 FITS; ≥48 confident FITS.

Walkway thresholds use standard ergonomic minimums; a confident mover may negotiate gaps tighter than the recommended tier.

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Will a queen size bed (152x203x36 cm) fit in a room?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Other assumptions

Similar calculations

Run your own fit check