Item Fits

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DOESN'T FIT

It doesn't fitby 6.5 in too large

Will an oversized chair (137x102x102 cm) fit in a space?

oversized chair· 4 ft 6 in × 3 ft 4 in × 3 ft 4 in

−6.5 in (−54%)too large at tightest point

Item being fitted

oversized chair4 ft 6 in × 3 ft 4 in × 3 ft 4 in

Space clearance

Space35 in × 6 ft 8 in

Result

6.5 in too large

▸ width axis · binding

Expert analysis

A oversized chair measuring 4 ft 6 in × 3 ft 4 in × 3 ft 4 in does not fit in a space, but it's about 6.5 in too large at the tightest point. The binding dimension is width: that is the axis where the oversized chair runs out of room. The persisted calculation steps support the reported tightest-point margin. One caveat: item is rigid and cannot be compressed, bent, or disassembled.

How we verified this

Binding axis: Width
Tightest clearance: 6.5 in over
Result: Width does not clear

−6.5 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
A 1.5 in handling allowance is already subtracted.

3 ft 4 in vs 34 in

Overage −6.5 in (−19.4%) on the WIDTH axis

AAxis inequality · opening width✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

40 \;\overset{?}{\le}\; 33.5\quad(\text{opening width})

↓ EVALUATE

40\,\text{in} \;>\; 33.5\,\text{in} \;\Longrightarrow\; \Delta = {-6.5}\,\text{in}

Plain English: Along the opening width, the item is 40 in and the space allows 33.5 in — over by 6.5 in.

BAxis inequality · opening height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

54 \;\overset{?}{\le}\; 78.5\quad(\text{opening height})

↓ EVALUATE

54\,\text{in} \;\le\; 78.5\,\text{in} \;\Longrightarrow\; \Delta = {+24.5}\,\text{in}

Plain English: Along the opening height, the item is 54 in and the space allows 78.5 in — 24.5 in to spare.

CDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{40^2 + 54^2} \;\overset{?}{\le}\; \sqrt{33.5^2 + 78.5^2}

↓ EVALUATE

67.2\,\text{in} \;\le\; 85.4\,\text{in} \;\Longrightarrow\; \Delta = {+18.1}\,\text{in}

Plain English: Tilted corner-to-corner the face spans 67.2 in, inside the opening's 85.4 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

D3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{54^2 + 40^2 + 40^2}

↓ EVALUATE

78.2\,\text{in} \;\le\; 85.4\,\text{in} \;\Longrightarrow\; \Delta = {+7.1}\,\text{in}

Plain English: Corner to corner the item reaches 78.2 in — keep that swing room in mind for the turn after.

EMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

40 + 1.5 = 41.5

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

FLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

33.5 - 1.5 = 32

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
3 ft 4 in×4 ft 6 in (front/back)	-6.5 in	24.5 in	✕	Too wide
3 ft 4 in×3 ft 4 in (sideways)	-6.5 in	38.5 in	✕	Too wide
3 ft 4 in×3 ft 4 in (sideways)	-6.5 in	38.5 in	✕	Too wide
3 ft 4 in×4 ft 6 in (laid flat)	-6.5 in	24.5 in	✕	Too wide
4 ft 6 in×3 ft 4 in (front/back)	-20.5 in	38.5 in	✕	Too wide
4 ft 6 in×3 ft 4 in (laid flat)	-20.5 in	38.5 in	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

Similar calculations

35 in wingback chair in a 32 in spaceDOESN'T FIT

34 in glider chair in a 27 in spaceDOESN'T FIT

3 ft chair in a 26 in spaceVERY TIGHT

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Will an oversized chair (137x102x102 cm) fit in a space?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Other assumptions

Similar calculations

Run your own fit check