Item Fits

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DOESN'T FIT

It doesn't fitby 1 ft 8 in too large

Will an outdoor rectangle dining set (417x249x76 cm) fit in a room?

outdoor rectangle dining set· 13 ft 8 in × 8 ft 2 in × 30 in

−1 ft 8 in (−37%)too large at tightest point

Item being fitted

outdoor rectangle dining set13 ft 8 in × 8 ft 2 in × 30 in

Space clearance

Room10 ft × 12 ft × 8 ft

Result

1 ft 8 in too large

▸ width axis · binding

See more outdoor rectangle dining set room calculations →

Expert analysis

A outdoor rectangle dining set measuring 164 in × 98 in × 30 in does not fit in a room, but it's about 1 ft 8 in too large at the tightest point.

How we verified this

Binding axis: Room long
Tightest clearance: 1 ft 8 in over
Result: Room long does not clear

−3 ft 8 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

Your outdoor rectangle dining set will not fit in the room — and it is clearly over the limit at the tightest point.

Handling: The item exceeds the space in every orientation — standard entry won't work.

13 ft 8 in vs 10 ft

Overage −3 ft 8 in (−36.7%) on the WIDTH axis

ARoom coverage ratio✓ PASS

\text{coverage} = \dfrac{A_{\text{item}}}{A_{\text{room}}}

↓ SUBSTITUTE

\dfrac{16072}{17282}

Plain English: Share of the room floor consumed by the placed item.

BAxis inequality · room long✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

164 \;\overset{?}{\le}\; 144\quad(\text{room long})

↓ EVALUATE

164\,\text{in} \;>\; 144\,\text{in} \;\Longrightarrow\; \Delta = {-20}\,\text{in}

Plain English: Along the room long, the item is 164 in and the space allows 144 in — over by 20 in.

CMinimum required space · room long✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

164 + 0 = 164

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

DLargest item that fits · room long✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

144 - 0 = 144

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

EDiagonal clearance · Pythagorean✕ FAIL

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{164^2 + 98^2} \;\overset{?}{\le}\; \sqrt{144^2 + 120^2}

↓ EVALUATE

191.1\,\text{in} \;>\; 187.4\,\text{in} \;\Longrightarrow\; \Delta = {-3.6}\,\text{in}

Plain English: Even tilted corner-to-corner the face spans 191.1 in, past the opening's 187.4 in diagonal — angling it doesn't recover the fit.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{98^2 + 164^2 + 30^2}

↓ EVALUATE

193.4\,\text{in} \;\le\; 210.6\,\text{in} \;\Longrightarrow\; \Delta = {+17.2}\,\text{in}

Plain English: Corner to corner the item reaches 193.4 in — keep that swing room in mind for the turn after.

Orientation	Strategy	Result
0° (as-is), short wall	—	✕
0° (as-is), long wall	—	✕
90° rotated, short wall	—	✕
90° rotated, long wall	—	✕
diagonal (1°–89°)	—	✕

How the room-fit check works

A room is a 2D footprint — width and depth matter for placement, plus the walkway gap left between the item and walls or other obstacles.

Place the item footprint inside the room rectangle in the orientation it will be used.
Compute walkway gaps from each item edge to every wall and to other obstacles in the room.
Take the minimum walkway gap — that’s the daily-traffic clearance the room must support.
Verdict ladder (getRoomVerdictTier): walkway <18 in DOESN'T_FIT; 18–24 VERY_TIGHT; 24–36 TIGHT; 36–48 FITS; ≥48 confident FITS.

Walkway thresholds use standard ergonomic minimums; a confident mover may negotiate gaps tighter than the recommended tier.

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Will an outdoor rectangle dining set (417x249x76 cm) fit in a room?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check