Item Fits

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DOESN'T FIT

It doesn't fitby 6 in too large

Will a wingback chair (88x95x105 cm) fit in a space?

wingback chair· 35 in × 3 ft 1 in × 3 ft 5 in

−6 in (−17%)too large at tightest point

Item being fitted

wingback chair35 in × 3 ft 1 in × 3 ft 5 in

Space clearance

Space30 in × 5 ft 11 in

Result

6 in too large

▸ width axis · binding

Expert analysis

A wingback chair measuring 35 in × 37 in × 41 in does not fit in a space, but it's about 6 in too large at the tightest point. The binding dimension is width: that is the axis where the wingback chair runs out of room. The persisted calculation steps support the reported tightest-point margin. One caveat: item is rigid and cannot be compressed, bent, or disassembled.

How we verified this

Binding axis: Width
Tightest clearance: 6 in over
Result: Width does not clear

−6 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
A 1 in handling allowance is already subtracted.

35 in vs 29 in

Overage −6 in (−21.4%) on the WIDTH axis

wingback chair · Axis inequality✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

34.6 \;\overset{?}{\le}\; 28.5\quad(\text{opening width})

↓ EVALUATE

34.6\,\text{in} \;>\; 28.5\,\text{in} \;\Longrightarrow\; \Delta = {-6.1}\,\text{in}

Plain English: Along the opening width, the item is 34.6 in and the space allows 28.5 in — over by 6.1 in.

wingback chair · Axis inequality✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

41.3 \;\overset{?}{\le}\; 69.9\quad(\text{opening height})

↓ EVALUATE

41.3\,\text{in} \;\le\; 69.9\,\text{in} \;\Longrightarrow\; \Delta = {+28.5}\,\text{in}

Plain English: Along the opening height, the item is 41.3 in and the space allows 69.9 in — 28.5 in to spare.

wingback chair · Diagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{34.6^2 + 41.3^2} \;\overset{?}{\le}\; \sqrt{28.5^2 + 69.9^2}

↓ EVALUATE

53.9\,\text{in} \;\le\; 75.5\,\text{in} \;\Longrightarrow\; \Delta = {+21.5}\,\text{in}

Plain English: Tilted corner-to-corner the face spans 53.9 in, inside the opening's 75.5 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

wingback chair · 3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{34.6^2 + 37.4^2 + 41.3^2}

↓ EVALUATE

65.6\,\text{in} \;\le\; 75.5\,\text{in} \;\Longrightarrow\; \Delta = {+9.8}\,\text{in}

Plain English: Corner to corner the item reaches 65.6 in — keep that swing room in mind for the turn after.

wingback chair · Minimum required space✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

34.6 + 1 = 35.6

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

wingback chair · Largest item that fits✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

28.5 - 1 = 27.6

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

wingback chair · Axis inequality✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

31.5 \;\overset{?}{\le}\; 28.5\quad(\text{opening width})

↓ EVALUATE

31.5\,\text{in} \;>\; 28.5\,\text{in} \;\Longrightarrow\; \Delta = {-3}\,\text{in}

Plain English: Along the opening width, the item is 31.5 in and the space allows 28.5 in — over by 3 in.

wingback chair · Axis inequality✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

41.3 \;\overset{?}{\le}\; 69.9\quad(\text{opening height})

↓ EVALUATE

41.3\,\text{in} \;\le\; 69.9\,\text{in} \;\Longrightarrow\; \Delta = {+28.5}\,\text{in}

Plain English: Along the opening height, the item is 41.3 in and the space allows 69.9 in — 28.5 in to spare.

wingback chair · Diagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{31.5^2 + 41.3^2} \;\overset{?}{\le}\; \sqrt{28.5^2 + 69.9^2}

↓ EVALUATE

52\,\text{in} \;\le\; 75.5\,\text{in} \;\Longrightarrow\; \Delta = {+23.5}\,\text{in}

Plain English: Tilted corner-to-corner the face spans 52 in, inside the opening's 75.5 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

wingback chair · 3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{34.6^2 + 31.5^2 + 41.3^2}

↓ EVALUATE

62.4\,\text{in} \;\le\; 75.5\,\text{in} \;\Longrightarrow\; \Delta = {+13}\,\text{in}

Plain English: Corner to corner the item reaches 62.4 in — keep that swing room in mind for the turn after.

wingback chair · Minimum required space✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

31.5 + 1 = 32.5

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

wingback chair · Largest item that fits✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

28.5 - 1 = 27.6

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
88 cm×105 cm (front/back)	-15 cm	73 cm	✕	Too wide
88 cm×95 cm (laid flat)	-15 cm	83 cm	✕	Too wide
95 cm×105 cm (sideways)	-22 cm	73 cm	✕	Too wide
95 cm×88 cm (laid flat)	-22 cm	90 cm	✕	Too wide
105 cm×88 cm (front/back)	-32 cm	90 cm	✕	Too wide
105 cm×95 cm (sideways)	-32 cm	83 cm	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

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Will a wingback chair (88x95x105 cm) fit in a space?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check