Will a Box (12x11x4 cm) Fit in a Container?

−0.5 in over

· ON THE DEPTH AXIS

It exceeds the opening at the tightest point.

The depth axis runs out of room.
Checked all 6 orientations — none fits.
A <1 in handling allowance is already subtracted.

4 in vs 4 in

Overage −0.5 in (−16.7%) on the DEPTH axis

AVolume inequality✓ PASS

\sum V_{\text{item}} \;\le\; V_{\text{container}}

↓ SUBSTITUTE

30.4 \;\overset{?}{\le}\; 82.1

Plain English: Packed together the item fills about 37% of the space's volume — plenty of room by volume.

BAxis inequality · width✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

4.6 \;\overset{?}{\le}\; 5.7\quad(\text{width})

↓ EVALUATE

4.6\,\text{in} \;\le\; 5.7\,\text{in} \;\Longrightarrow\; \Delta = +1.1\,\text{in}

Plain English: Along the width, the item is 4.6 in and the space allows 5.7 in — 1.1 in to spare.

CAxis inequality · depth✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

4.4 \;\overset{?}{\le}\; 3.8\quad(\text{depth})

↓ EVALUATE

4.4\,\text{in} \;>\; 3.8\,\text{in} \;\Longrightarrow\; \Delta = -0.6\,\text{in}

Plain English: Along the depth, the item is 4.4 in and the space allows 3.8 in — over by 0.6 in.

DAxis inequality · height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

1.5 \;\overset{?}{\le}\; 3.8\quad(\text{height})

↓ EVALUATE

1.5\,\text{in} \;\le\; 3.8\,\text{in} \;\Longrightarrow\; \Delta = +2.3\,\text{in}

Plain English: Along the height, the item is 1.5 in and the space allows 3.8 in — 2.3 in to spare.

EDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{4.6^2 + 4.4^2} \;\overset{?}{\le}\; \sqrt{5.7^2 + 3.8^2}

↓ EVALUATE

6.4\,\text{in} \;\le\; 6.9\,\text{in} \;\Longrightarrow\; \Delta = +0.5\,\text{in}

Plain English: Tilted corner-to-corner the face spans 6.4 in, inside the opening's 6.9 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{4.6^2 + 4.4^2 + 1.5^2}

↓ EVALUATE

6.5\,\text{in} \;\le\; 7.8\,\text{in} \;\Longrightarrow\; \Delta = +1.3\,\text{in}

Plain English: Corner to corner the item reaches 6.5 in — keep that swing room in mind for the turn after.

Orientation	L	W	H	Result	Note
117×112×38mm (Upright)	—	1 in	2.5 in	✕	Depth
117×38×112mm (On its side)	—	1 in	-0.5 in	✕	Height
112×117×38mm (Rotated 90°)	—	1.5 in	2.5 in	✕	Depth
112×38×117mm (On its side)	—	1.5 in	-1 in	✕	Height
38×117×112mm (On its side)	—	4.5 in	-0.5 in	✕	Depth
38×112×117mm (On its side)	—	4.5 in	-1 in	✕	Height

How the container-fit check works

A container is a fully 3D box — length, width, AND height must accept the item simultaneously; corner reachability is a soft second constraint.

Treat the container as a 3D box and generate the item’s 6 dimension permutations (3 axes × 2 flips).
For each permutation, apply the constraint: item ≤ container on length, width, and height simultaneously.
Check reachability — items longer than arm’s reach can’t be loaded all the way into the back corners.
Subtract 1.5 in handling clearance on each axis for the mover’s grip plus pivot room.
Verdict ladder (verdict-tiers.js, shared with door): FITS ≥ 2 in; FITS_TIGHT 0.5–2 in; FITS_VERY_TIGHT 0–0.5 in; DOESN'T_FIT below.

Interior dimensions use the published spec; door rails, ribs, and floor lashings can shave 1–2 in off the usable corners.

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Will a box (12x11x4 cm) fit in a container?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check