Item Fits

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DOESN'T FIT

It doesn't fitby 3 ft 8 in too large

Will a queen mattress (152x203x25 cm) fit in a room?

queen mattress· 5 ft × 6 ft 8 in × 10 in

−3 ft 8 in (−122%)too large at tightest point

Item being fitted

queen mattress5 ft × 6 ft 8 in × 10 in

Space clearance

Room36 in × 36 in × 8 ft

Result

3 ft 8 in too large

▸ depth axis · binding

See more queen mattress room calculations →

Expert analysis

A queen mattress measuring 60 in × 80 in × 10 in does not fit in a room, but it's about 3 ft 8 in too large at the tightest point. One caveat: item is rigid and cannot be compressed, bent, or disassembled.

How we verified this

Binding axis: Room long
Tightest clearance: 3 ft 8 in over
Result: Room long does not clear

−3 ft 8 in over

· ON THE DEPTH AXIS

It exceeds the opening at the tightest point.

Your queen mattress will not fit in the room — and it is clearly over the limit at the tightest point.

Handling: The item exceeds the space in every orientation — standard entry won't work.

6 ft 8 in vs 36 in

Overage −3 ft 8 in (−122.3%) on the DEPTH axis

ARoom coverage ratio✕ FAIL

\text{coverage} = \dfrac{A_{\text{item}}}{A_{\text{room}}}

↓ SUBSTITUTE

\dfrac{4800}{1295}

Plain English: Share of the room floor consumed by the placed item.

BAxis inequality · room long✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

80 \;\overset{?}{\le}\; 36\quad(\text{room long})

↓ EVALUATE

80\,\text{in} \;>\; 36\,\text{in} \;\Longrightarrow\; \Delta = {-44}\,\text{in}

Plain English: Along the room long, the item is 80 in and the space allows 36 in — over by 44 in.

CMinimum required space · room long✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

80 + 0 = 80

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

DLargest item that fits · room long✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

36 - 0 = 36

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

EDiagonal clearance · Pythagorean✕ FAIL

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{80^2 + 60^2} \;\overset{?}{\le}\; \sqrt{36^2 + 36^2}

↓ EVALUATE

100\,\text{in} \;>\; 50.9\,\text{in} \;\Longrightarrow\; \Delta = {-49.1}\,\text{in}

Plain English: Even tilted corner-to-corner the face spans 100 in, past the opening's 50.9 in diagonal — angling it doesn't recover the fit.

F3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{60^2 + 80^2 + 10^2}

↓ EVALUATE

100.5\,\text{in} \;\le\; 108.7\,\text{in} \;\Longrightarrow\; \Delta = {+8.2}\,\text{in}

Plain English: Corner to corner the item reaches 100.5 in — keep that swing room in mind for the turn after.

Orientation	Strategy	Result
0° (as-is)	—	✕
90° rotated	—	✕
diagonal (1°–89°)	—	✕

How the room-fit check works

A room is a 2D footprint — width and depth matter for placement, plus the walkway gap left between the item and walls or other obstacles.

Place the item footprint inside the room rectangle in the orientation it will be used.
Compute walkway gaps from each item edge to every wall and to other obstacles in the room.
Take the minimum walkway gap — that’s the daily-traffic clearance the room must support.
Verdict ladder (getRoomVerdictTier): walkway <18 in DOESN'T_FIT; 18–24 VERY_TIGHT; 24–36 TIGHT; 36–48 FITS; ≥48 confident FITS.

Walkway thresholds use standard ergonomic minimums; a confident mover may negotiate gaps tighter than the recommended tier.

Similar calculations

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Will a queen mattress (152x203x25 cm) fit in a room?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check