Item Fits

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DOESN'T FIT

It doesn't fitby 7.5 in too large

Will a cube (91x91x91 cm) fit in a space?

cube· 36 in × 36 in × 36 in

−7.5 in (−20%)too large at tightest point

Item being fitted

cube36 in × 36 in × 36 in

Space clearance

Space30 in × 5 ft

Result

7.5 in too large

▸ width axis · binding

Expert analysis

A cube measuring 36 in × 36 in × 36 in does not fit in a space, but it's about 7.5 in too large at the tightest point. The binding dimension is width: that is the axis where the cube runs out of room. The persisted calculation steps support the reported tightest-point margin. One caveat: item is rigid and cannot be compressed, bent, or disassembled.

How we verified this

Binding axis: Width
Tightest clearance: 7.5 in over
Result: Width does not clear

−7.5 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
A 1.5 in handling allowance is already subtracted.

36 in vs 29 in

Overage −7.5 in (−26.2%) on the WIDTH axis

AAxis inequality · opening width✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

36 \;\overset{?}{\le}\; 28.5\quad(\text{opening width})

↓ EVALUATE

36\,\text{in} \;>\; 28.5\,\text{in} \;\Longrightarrow\; \Delta = {-7.5}\,\text{in}

Plain English: Along the opening width, the item is 36 in and the space allows 28.5 in — over by 7.5 in.

BAxis inequality · opening height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

36 \;\overset{?}{\le}\; 58.5\quad(\text{opening height})

↓ EVALUATE

36\,\text{in} \;\le\; 58.5\,\text{in} \;\Longrightarrow\; \Delta = {+22.5}\,\text{in}

Plain English: Along the opening height, the item is 36 in and the space allows 58.5 in — 22.5 in to spare.

CDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{36^2 + 36^2} \;\overset{?}{\le}\; \sqrt{28.5^2 + 58.5^2}

↓ EVALUATE

50.9\,\text{in} \;\le\; 65.1\,\text{in} \;\Longrightarrow\; \Delta = {+14.2}\,\text{in}

Plain English: Tilted corner-to-corner the face spans 50.9 in, inside the opening's 65.1 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

D3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{36^2 + 36^2 + 36^2}

↓ EVALUATE

62.3\,\text{in} \;\le\; 65.1\,\text{in} \;\Longrightarrow\; \Delta = {+2.8}\,\text{in}

Plain English: Corner to corner the item reaches 62.3 in — keep that swing room in mind for the turn after.

EMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

36 + 1.5 = 37.5

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

FLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

28.5 - 1.5 = 27

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
36 in×36 in (front/back)	-7.5 in	22.5 in	✕	Too wide
36 in×36 in (front/back)	-7.5 in	22.5 in	✕	Too wide
36 in×36 in (sideways)	-7.5 in	22.5 in	✕	Too wide
36 in×36 in (sideways)	-7.5 in	22.5 in	✕	Too wide
36 in×36 in (laid flat)	-7.5 in	22.5 in	✕	Too wide
36 in×36 in (laid flat)	-7.5 in	22.5 in	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

Similar calculations

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Will a cube (91x91x91 cm) fit in a space?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Other assumptions

Similar calculations

Run your own fit check