Item Fits

VERY TIGHT

It fitswith 0.5 in to spare

Will a fridge (91x86x178 cm) fit in a space?

fridge· 36 in × 34 in × 5 ft 10 in

+0.5 in (−3%)of clearance at tightest point

Item being fitted

fridge36 in × 34 in × 5 ft 10 in

Space clearance

Space35 in × 6 ft 8 in

Result

0.5 in of clearance

▸ width axis · binding

Expert analysis

A fridge measuring 36 in × 34 in × 70 in is a very tight fit in a space, with about 0.5 in to spare at the tightest point. The binding dimension is height: in its best-fitting orientation, the height is what comes closest to the limit, and it still clears. That margin already subtracts a 1.5 in handling allowance, so it reflects a realistic load rather than a paper-thin theoretical fit. One caveat: applied practical clearance for handling (see tolerance buffer above).

How we verified this

Tightest clearance: 0.5 in clear
Orientations checked: 6
Result: Fits in its best orientation

+0.5 in clearance

· ON THE HEIGHT AXIS

It fits, with almost no clearance.

The height axis is the tightest, and it still clears.
A 1.5 in handling allowance is already subtracted.
No tilting or compression needed.

Clearance +0.5 in at the tightest point

AOptimal diagonal angle✓ PASS

\theta_{\text{opt}} = \arctan\!\left(\dfrac{h}{w}\right)

↓ SUBSTITUTE

\arctan\!\left(\dfrac{36}{34}\right)

Plain English: Closed-form angle that minimizes the rotated bounding box height.

BMinimum projected height at diagonal✓ PASS

h_{\min} = \dfrac{2\,w\,h}{\sqrt{w^2 + h^2}}

↓ SUBSTITUTE

\dfrac{2 \cdot 34 \cdot 36}{\sqrt{34^2 + 36^2}}

Plain English: Smallest projected height achievable when rotating the item.

CProjected width at angle✕ FAIL

\text{projW}(\theta) = w\cos\theta + h\sin\theta

↓ SUBSTITUTE

34\cos(1^\circ) + 36\sin(1^\circ)

Plain English: Width of the item rotated by θ.

DProjected height at angle✓ PASS

\text{projH}(\theta) = w\sin\theta + h\cos\theta

↓ SUBSTITUTE

34\sin(1^\circ) + 36\cos(1^\circ)

Plain English: Height of the item rotated by θ.

EDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{34.4^2 + 36.3^2} \;\overset{?}{\le}\; \sqrt{33.5^2 + 78.5^2}

↓ EVALUATE

50\,\text{in} \;\le\; 85.4\,\text{in} \;\Longrightarrow\; \Delta = +35.4\,\text{in}

Plain English: Tilted corner-to-corner the face spans 50 in, inside the opening's 85.4 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

F3D space diagonal✕ FAIL

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{36^2 + 34^2 + 70^2}

↓ EVALUATE

85.7\,\text{in} \;>\; 85.4\,\text{in} \;\Longrightarrow\; \Delta = -0.4\,\text{in}

Plain English: Corner to corner the item reaches 85.7 in — keep that swing room in mind for the turn after.

GMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

34.4 + 1.5 = 35.9

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

HLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

33.5 - 1.5 = 32

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
✓ chosen34 in×3 ft @ 1° (laid flat)	-1 in	3 ft 6 in	✓
34 in×5 ft 10 in (sideways)	-1 in	8.5 in	✓
34 in×5 ft 10 in (sideways)	-0.5 in	8.5 in	✕	Too wide
34 in×36 in (laid flat)	-0.5 in	3 ft 6.5 in	✕	Too wide
36 in×5 ft 10 in (front/back)	-2.5 in	8.5 in	✕	Too wide
36 in×34 in (laid flat)	-2.5 in	3 ft 8.5 in	✕	Too wide
5 ft 10 in×36 in (front/back)	-36.5 in	3 ft 6.5 in	✕	Too wide
5 ft 10 in×34 in (sideways)	-36.5 in	3 ft 8.5 in	✕	Too wide

Margins shown are calculated; allow ±¼ in for tape-measure precision.

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

Similar calculations

3 ft french-door fridge in a 36 in spaceVERY TIGHT

3 ft fridge in a 35 in spaceDOESN'T FIT

33 in french door fridge in a 33 in spaceDOESN'T FIT

33 in french door fridge in a 35 in spaceFITS TIGHT

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Will a fridge (91x86x178 cm) fit in a space?

Expert analysis

It fits, with almost no clearance.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check