Item Fits

DOESN'T FIT

It doesn't fitby 1.5 in too large

Will a french door fridge (84x86x178 cm) fit in a space?

french door fridge· 33 in × 34 in × 5 ft 10 in

−1.5 in (+0%)too large at tightest point

Item being fitted

french door fridge33 in × 34 in × 5 ft 10 in

Space clearance

Space33 in × 6 ft 8 in

Result

1.5 in too large

▸ width axis · binding

Expert analysis

A french door fridge measuring 33 in × 34 in × 70 in does not fit in a space, but it's about 1.5 in too large at the tightest point. The binding dimension is width: that is the axis where the french door fridge runs out of room. We checked every orientation, and none places the french door fridge fully inside. One caveat: applied practical clearance for handling (see tolerance buffer above).

How we verified this

Binding axis: Width
Tightest clearance: 1.5 in over
Orientations checked: 6
Result: Width exceeds the opening

−1.5 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
Checked all 6 orientations — none fits.
A 1.5 in handling allowance is already subtracted.

33 in vs 31 in

Overage −1.5 in (−4.8%) on the WIDTH axis

AAxis inequality · opening width✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

33 \;\overset{?}{\le}\; 31.5\quad(\text{opening width})

↓ EVALUATE

33\,\text{in} \;>\; 31.5\,\text{in} \;\Longrightarrow\; \Delta = -1.5\,\text{in}

Plain English: Along the opening width, the item is 33 in and the space allows 31.5 in — over by 1.5 in.

BAxis inequality · opening height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

70 \;\overset{?}{\le}\; 78.5\quad(\text{opening height})

↓ EVALUATE

70\,\text{in} \;\le\; 78.5\,\text{in} \;\Longrightarrow\; \Delta = +8.5\,\text{in}

Plain English: Along the opening height, the item is 70 in and the space allows 78.5 in — 8.5 in to spare.

CDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{33^2 + 70^2} \;\overset{?}{\le}\; \sqrt{31.5^2 + 78.5^2}

↓ EVALUATE

77.4\,\text{in} \;\le\; 84.6\,\text{in} \;\Longrightarrow\; \Delta = +7.2\,\text{in}

Plain English: Tilted corner-to-corner the face spans 77.4 in, inside the opening's 84.6 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

D3D space diagonal✓ PASS

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{33^2 + 34^2 + 70^2}

↓ EVALUATE

84.5\,\text{in} \;\le\; 84.6\,\text{in} \;\Longrightarrow\; \Delta = +0.1\,\text{in}

Plain English: Corner to corner the item reaches 84.5 in — keep that swing room in mind for the turn after.

EMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

33 + 1.5 = 34.5

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

FLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

31.5 - 1.5 = 30

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
33 in×5 ft 10 in (front/back)	-1.5 in	8.5 in	✕	Too wide
33 in×34 in (laid flat)	-1.5 in	3 ft 8.5 in	✕	Too wide
34 in×5 ft 10 in (sideways)	-2.5 in	8.5 in	✕	Too wide
34 in×33 in (laid flat)	-2.5 in	3 ft 9.5 in	✕	Too wide
5 ft 10 in×33 in (front/back)	-38.5 in	3 ft 9.5 in	✕	Too wide
5 ft 10 in×34 in (sideways)	-38.5 in	3 ft 8.5 in	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

Similar calculations

33 in french door fridge in a 35 in spaceFITS TIGHT

33 in fridge in a 31 in spaceDOESN'T FIT

3 ft french-door fridge in a 36 in spaceVERY TIGHT

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Will a french door fridge (84x86x178 cm) fit in a space?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check