Will a 315 width (80x208x95 cm) Fit Through an 80 cm Door?

−1.5 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
Checked all 6 orientations — none fits.
A 1.5 in handling allowance is already subtracted.

31 in vs 30 in

Overage −1.5 in (−5.0%) on the WIDTH axis

AAxis inequality · opening width✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

31.5 \;\overset{?}{\le}\; 30\quad(\text{opening width})

↓ EVALUATE

31.5\,\text{in} \;>\; 30\,\text{in} \;\Longrightarrow\; \Delta = -1.5\,\text{in}

Plain English: Along the opening width, the item is 31.5 in and the space allows 30 in — over by 1.5 in.

BAxis inequality · opening height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

37.2 \;\overset{?}{\le}\; 78.5\quad(\text{opening height})

↓ EVALUATE

37.2\,\text{in} \;\le\; 78.5\,\text{in} \;\Longrightarrow\; \Delta = +41.3\,\text{in}

Plain English: Along the opening height, the item is 37.2 in and the space allows 78.5 in — 41.3 in to spare.

CDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{31.5^2 + 37.2^2} \;\overset{?}{\le}\; \sqrt{30^2 + 78.5^2}

↓ EVALUATE

48.8\,\text{in} \;\le\; 84.1\,\text{in} \;\Longrightarrow\; \Delta = +35.3\,\text{in}

Plain English: Tilted corner-to-corner the face spans 48.8 in, inside the opening's 84.1 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

D3D space diagonal✕ FAIL

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{31.5^2 + 82^2 + 37.2^2}

↓ EVALUATE

95.4\,\text{in} \;>\; 84.1\,\text{in} \;\Longrightarrow\; \Delta = -11.4\,\text{in}

Plain English: Corner to corner the item reaches 95.4 in — keep that swing room in mind for the turn after.

EMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

31.5 + 1.5 = 33

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

FLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

30 - 1.5 = 28.5

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
31.5×37.2" (front/back)	0"	42.8"	✕	Too wide
31.5×82" (laid flat)	0"	-2"	✕	Too wide
37.2×31.5" (front/back)	-5.7"	48.5"	✕	Too wide
37.2×82" (sideways)	-5.7"	-2"	✕	Too wide
82×37.2" (sideways)	-50.5"	42.8"	✕	Too wide
82×31.5" (laid flat)	-50.5"	48.5"	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

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Will a 315 width (80x208x95 cm) fit through an 80 cm door?

Expert analysis

It exceeds the opening at the tightest point.

Dimensions

Space geometry

Handling

Similar calculations

Run your own fit check