Will a fridge dimensions (75x203x178 cm) Fit Through a 75 cm Door?

Will a fridge dimensions (75x203x178 cm) Fit Through a 75 cm Door?

−1.5 in over

· ON THE WIDTH AXIS

It exceeds the opening at the tightest point.

The width axis runs out of room.
Checked all 6 orientations — none fits.
A 1.5 in handling allowance is already subtracted.

29 in vs 28 in

Overage −1.5 in (−5.3%) on the WIDTH axis

AAxis inequality · opening width✕ FAIL

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

29.5 \;\overset{?}{\le}\; 28\quad(\text{opening width})

↓ EVALUATE

29.5\,\text{in} \;>\; 28\,\text{in} \;\Longrightarrow\; \Delta = -1.5\,\text{in}

Plain English: Along the opening width, the item is 29.5 in and the space allows 28 in — over by 1.5 in.

BAxis inequality · opening height✓ PASS

d_{\text{item}} \;\le\; d_{\text{space}}

↓ SUBSTITUTE

70 \;\overset{?}{\le}\; 78.5\quad(\text{opening height})

↓ EVALUATE

70\,\text{in} \;\le\; 78.5\,\text{in} \;\Longrightarrow\; \Delta = +8.5\,\text{in}

Plain English: Along the opening height, the item is 70 in and the space allows 78.5 in — 8.5 in to spare.

CDiagonal clearance · Pythagorean✓ PASS

\sqrt{a^2 + b^2} \;\le\; \sqrt{a_{\text{sp}}^2 + b_{\text{sp}}^2}

↓ SUBSTITUTE

\sqrt{29.5^2 + 70^2} \;\overset{?}{\le}\; \sqrt{28^2 + 78.5^2}

↓ EVALUATE

75.9\,\text{in} \;\le\; 83.3\,\text{in} \;\Longrightarrow\; \Delta = +7.4\,\text{in}

Plain English: Tilted corner-to-corner the face spans 75.9 in, inside the opening's 83.3 in diagonal — but a tilt only buys diagonal room, it can't widen the throat.

D3D space diagonal✕ FAIL

\mathcal{D}_{3D} = \sqrt{L^2 + W^2 + H^2}

↓ SUBSTITUTE

\sqrt{29.5^2 + 80^2 + 70^2}

↓ EVALUATE

110.3\,\text{in} \;>\; 83.3\,\text{in} \;\Longrightarrow\; \Delta = -27\,\text{in}

Plain English: Corner to corner the item reaches 110.3 in — keep that swing room in mind for the turn after.

EMinimum required space · opening width✕ FAIL

d_{\text{req}} = d_{\text{item}} + t

↓ SUBSTITUTE

29.5 + 1.5 = 31

Plain English: Smallest space on the limiting axis that would admit this item (with handling tolerance).

FLargest item that fits · opening width✕ FAIL

d_{\max} = d_{\text{space}} - t

↓ SUBSTITUTE

28 - 1.5 = 26.5

Plain English: Largest item dimension this space admits on the limiting axis (after handling tolerance).

Orientation	Width	Height	Result	Note
29.5×70" (front/back)	0"	10"	✕	Too wide
29.5×80" (laid flat)	0"	0"	✕	Too wide
70×29.5" (front/back)	-40.5"	50.5"	✕	Too wide
70×80" (sideways)	-40.5"	0"	✕	Too wide
80×70" (sideways)	-50.5"	10"	✕	Too wide
80×29.5" (laid flat)	-50.5"	50.5"	✕	Too wide

How the door-passage check works

A door is a 2D opening — width and height matter; depth (path length through the doorway) doesn’t.

Generate all 6 dimension permutations of the item (3 axes × 2 flips).
For each permutation, apply the door constraint: item_width ≤ door_width AND item_height ≤ door_height.
Subtract 1.5 in handling clearance from each axis to leave room for human movement.
Pick the permutation with the largest minimum-axis margin — that’s the orientation a mover would choose.
Verdict ladder (verdict-tiers.js): FITS if margin ≥ 2 in; FITS_TIGHT if 0.5–2 in; FITS_VERY_TIGHT if 0–0.5 in; DOESN'T_FIT below.

Tolerance ±¼ in (6 mm) is applied implicitly (band promotion to FITS_VERY_TIGHT) — see the note below the orientation matrix.

Similar calculations

29 in fridge dimensions through a 32 in doorwayDOESN'T FIT

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